Question

Tolong nomor 14,15,16 .terima kasih ya

Answer 1

14) x²+5x+4 = 0
(x+1)(x+4) = 0
x = -1 atau x = -4
jadi, x2 adalah -1(C)


15) p²+2p = 3 ------>> p²+2p-3 = 0
(p-1)(p+3) = 0
p = 1 atau p = -3
jadi, akar3nya adalah (-3,1) (A)



17) 2x²+5x-3 = 0
(2x-1)(x+3) = 0
2x = 1 atau x = -3
x = 1/2
jadi, akar2nya adalah (-3,1/2) (A)

Answer 2

X1 = -4
x + 4 = 0

x² + 5x + 4 = 0
(x + 4)(x + 1)

x + 1 = 0
x = -1
---> C.

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p² + 2p = 3
p² + 2p - 3 = 0
(p + 3)(p - 1)
p + 3 = 0
p = -3

p - 1 = 0
p = 1

= (-3, 1)
---> A.

==========

2x² + 5x - 3 = 0
(2x - 1)(x + 3)
2x - 1 = 0
2x = 1
x = 1/2

x + 3 = 0
x = -3

= (-3, 1/2)
---> A.