Question

Tolong nomor 10-20 guyss... makasi bgttt

Answer 1

11. (3x-2)²/(4x+3)² = (x(3 - 2/x))²/(x(4 + 3/x))²

                           = (x²(3 - 2/x)²)/(x²(4 + 3/x)²)

                           = (3 - 2/x)²/(4 + 3/x)²  <= masukkan x = ∞

                           = (3-0)²/(4+0)²

                          = 3²/4²

12.f(x) = 3x⁴-4x²+x-6

f'(x) = 4.3x³-2.4x+1

f'(x) = 12x³-8x+1

13.f(x) = x²+8x-3

f'(x) = 2x+8

f'(3) = 2.3+8 = 14

14. y = (x²+1)(x³-1)

y = x⁵-x²+x³-1

y' = 5x⁴-2x+3x²

y' = 5x⁴+3x²-2x

15. Lakukan pembagian horner :

            3       5

x = -4            -12

            3      -7

hasil : y = 3 - 7/(x+4)

y' = 0 - (-7/(x+4)²)

y' = 7/(x+4)²

15. Naik :

y' > 0

3.4x²-2.6x > 0

12x²-12x > 0

12x(x-1) > 0

12x > 0 atau x > 1

x > 0 atau x > 1

x > 1

16. maksimum ketika y' = 0

y' = 0 = 12x²-36x+15

0 = 4x²-12x+5

0 = (2x-1)(2x-5)

2x = 1 atau 2x = 5

x = 1/2 atau x = 5/2

karena 5/2 > 1/2, maka nilai maksimum tercapai ketika x = 5/2

19. sama dengan nomor 14

20.y' = 2x-8 <= x = 2

y' = 2.2-8 = -4

persamaan garis singgung nya :

y+7 = -4(x-2)

y+7 = -4x+8

y+4x = 1

y+4x-1 = 0

4x+y-1 = 0