Question

Tolong nomer 21 sama 22 dongskiii

Answer 1

21.

⁶log 5 . ⁵log 4 = ab

⁶log 4 = ab

⁴log 6 = 1/ab

⁴log 0,24

= ⁴log 24/100

= ⁴log 24 - ⁴log 100

= (⁴log 4 + ⁴log 6) - (⁴log 5² + ⁴log 4)

= (1 + 1/ab) - (2(1/b) + 1)

= ((ab + 1)/ab - (2 + b)/b

22.

⁶log 98 = (⁷log 89)/(⁷log 6)

            = (⁷log (2 x 7²))/(⁷log (2x3))

           = (⁷log 2 + 2.⁷log 7)/(⁷log 2 + ⁷log 3)

           = (a + 2) / (a + ab)

Answer 2

Penjelasan dengan langkah-langkah:

no. 21

⁶log5 = a

⁵log4 = b

⁴log0,24

= ⁴log (24/100)

= ⁴log24 - ⁴log100

= (⁴log4 + ⁴log6) - (⁴log5²x4)

= ⁴log4 + ⁴log6 - (2⁴log5 + ⁴log4)

= ⁴log4 + ⁴log6 - 2⁴log5 - ⁴log4

= ⁴log6 - 2⁴log5

= ⁵log6/⁵log4 - 2⁴log5

= (1/⁶log5. ⁵log4) - 2/⁵log4

= 1/ab - 2/b

= 1/ab - 2a/ab

= (1 - 2a)/ab.......(A)

.

no.22

⁷log2 = a

²log3 = b

⁶log98

= ⁶log(2 x 7²)

= ⁶log2 + ⁶log7²

= ⁶log2 + 2⁶log7

= (²log2/²log6) + 2/(²log7/²log6)

= 1/(²log2 + ²log3) + 2/⁷log2 (²log2 + ²log3)

= 1/(1 + b) + 2/a((1 + b)

= 1/(1 + b) + 2/(a(1 + b)

= a/a(1 + b) + 2/a(1 + b)

= (a + 2)/(a + ab) ......(E)