Question

Tolong No.5 dan 6 ya..Menyederhanakan logaritma dan Persamaan kuadrat

Answer 1

Yg atasnya dlu pecahin:
6log6^3 +2^1/2log2^4 x 2^2log 2^5
->3+(2/1x4)x5/2
3+8x5/2
=23
trus yg bawahnya:
3log54/2
->3log3^3
-> 3
jadi isinya :
23/3
yg nomor 6
x1+x2=3p
x1.x2=4p+2
jadi
1/x1 +1/x2 =p+1/4
(x1+x2)/x1.x2=p+1/4
jadi
(3p/4p+2)=(p+1)/4
kali silang :
12p=(p+1)(4p+2)
4p^2-6p+2
->>> 1/4(4p-2)(4p-4)
4p=2. 4p=4
p=1
p=1/2.