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A kejadian mata dadu < 6 .
A = { 1, 2, 3, 4, 5 }. n(A) = 5
P(A) = n(A)/n(S) = 5/6
19) 0,4 × 40 = 16 orang
20) 5/10×3/9×2/8
= 30/720
= 3/72
= 1/24
1) huruf A ada 2, banyak huruf 10
P(A) = 2/10 = 1/5
2) As hitam ada 2, banyak As 4
P(As) = 2/4 = 1/2
3) Peluang mtk = 1/3
4) P(A)complemen = 1- P(A)
= 1 - 0,3 = 0,7
5) Prima atau genap { 2,3,4,5,6 }
n = 5
P(prima v genap) = 5/6
6)1 angka dan 2 gambar.
{ (a,g,g) ,(g,a,g),( g,g,a)} n = 3
n(S) = 2×2×2= 8
P(E) = 3/8
7) Angka dan dadu prima
{ (a,2),(a, 3),(a, 5) }==> n = 3
n(S) = 2×6 = 12
P(A) = 3/12 = 1/4
8)P(merah) = 10/15= 2/3
9) n(S) = 6×6 = 36
A ={ (4,6),(5,5),(5,6),(6,5),(6,4)}==> n = 5
P(A) = 5/36
frekuensi harapan= 5/36×108
= 15 kali
10) P(merah ) = 10/37
1) 4/10×3/5 = 12/50 = 6/25
2) P(A) = 4/10+3/10 = 7/10