(x⁵-2x⁴+3x²-2)/(3x⁵-2x+1) = x⁵(1-2/x+3/x³-2/x⁵)/x⁵(3-2/x⁴+1/x⁵)
= (1-2/x+3/x³-2/x⁵)/(3-2/x⁴+1/x⁵)
kalau dimasukkan nilai x = ∞ , semuannya akan jadi 0 kecuali konstanta (bilangan tanpa x) , jadinya :
= (1-0+0-0)/(3-0+0) = 1/3
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(x⁵-2x⁴+3x²-2)/(3x⁵-2x+1) = x⁵(1-2/x+3/x³-2/x⁵)/x⁵(3-2/x⁴+1/x⁵)
= (1-2/x+3/x³-2/x⁵)/(3-2/x⁴+1/x⁵)
kalau dimasukkan nilai x = ∞ , semuannya akan jadi 0 kecuali konstanta (bilangan tanpa x) , jadinya :
= (1-0+0-0)/(3-0+0) = 1/3