t = 15 + 15 = 30 a = 50-10 = 40 luas = L1 + L2 = ( 1/2 x a x t) + ( p x l ) = ( 1/2 x 50 x 30) + ( 10 x 15) =750+150 = 900 cm²
jawaban soal nomer 3 kliling = 3s + 1/2 π d = 3(42) + (1/2 x 22/7 x 42) = 126 + 66 = 192 cm luas = L1 - L2 = ( s x s ) - ( 1/2 x π x r²) = (42 x 42) - ( 1/2 x 22/7 x 21 x 21) = 1764 - (11 x 3 x 21) = 1764 - 693 = 1071 cm²
jawaban soal nomer 4 kliling = 2(12) + 8 + 6 + 10 = 24 + 24 = 48 cm t = √ 10² - 6² = √100-36 = √ 64 = 8 luas = L1 + L2 = ( a x t) + ( 1/2 x a x t) = ( 10 x 8) + (1/2 x 8 x 6) = 80 + 24 = 104 cm²
jwaban soal nomer 5 kliling = 2 (20+13) + 1/2 x π x d = 2 (32) + (1/2 x 3,14 x 20) = 64 + 31,4 = 95,4 cm
luas = persegi - segitiga - 1/2lingkaran = s x s - 1/2 x a x t- 1/2 xπxr² = 20 x 20 - 1/2 x 20 x 6 - 1/2 x 3,14 x 10 x 10 = 400 - 60 - 157 = 183
kliling = 2 (10+20)
= 2(30)
= 60
l = 10 - 5
= 5
luas = L1 + L2
= p x l + p x l
= 20 x 5 + 5x5
= 100 + 25
= 125 cm²
jawaban soal nomer 2
kliling = 2(41+15) +20+10
= 2 ( 56) +30
= 112+30
= 142
t = 15 + 15
= 30
a = 50-10
= 40
luas = L1 + L2
= ( 1/2 x a x t) + ( p x l )
= ( 1/2 x 50 x 30) + ( 10 x 15)
=750+150
= 900 cm²
jawaban soal nomer 3
kliling = 3s + 1/2 π d
= 3(42) + (1/2 x 22/7 x 42)
= 126 + 66
= 192 cm
luas = L1 - L2
= ( s x s ) - ( 1/2 x π x r²)
= (42 x 42) - ( 1/2 x 22/7 x 21 x 21)
= 1764 - (11 x 3 x 21)
= 1764 - 693
= 1071 cm²
jawaban soal nomer 4
kliling = 2(12) + 8 + 6 + 10
= 24 + 24
= 48 cm
t = √ 10² - 6²
= √100-36
= √ 64
= 8
luas = L1 + L2
= ( a x t) + ( 1/2 x a x t)
= ( 10 x 8) + (1/2 x 8 x 6)
= 80 + 24
= 104 cm²
jwaban soal nomer 5
kliling = 2 (20+13) + 1/2 x π x d
= 2 (32) + (1/2 x 3,14 x 20)
= 64 + 31,4
= 95,4 cm
luas = persegi - segitiga - 1/2lingkaran
= s x s - 1/2 x a x t- 1/2 xπxr²
= 20 x 20 - 1/2 x 20 x 6 - 1/2 x 3,14 x 10 x 10
= 400 - 60 - 157
= 183