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x + 2y + z = 1 ... (2)
x + 4y - 2z = 18 ... (3)
Eliminasi persamaan (1) dan (2)
2x + 3y - z = 16 | x 1 | 2x + 3y - z = 16
x + 2y + z = 1 | x 2 | 2x + 4y + 2z = 2
----------------------- -
- y - 3z = 14 ... (4)
Eliminasi persamaan (2) dan (3)
x + 2y + z = 1
x + 4y - 2z = 18
---------------------- -
- 2y + 3z = - 17 ... (5)
Eliminasi persamaan (4) dan (5)
- y - 3z = 14
- 2y + 3z = - 17
--------------------- +
- 3y = - 3
y = -3/-3
y = 1
Subtitusi y = 1 ke persamaan (4)
- y - 3z = 14
- 1 - 3z = 14
- 3z = 14 + 1
- 3z = 15
z = 15/-3
z = - 5
Subtitusi y = 1 dan z = - 5 ke persamaan (2)
x + 2y + z = 1
x + 2(1) + (- 5) = 1
x + 2 - 5 = 1
x - 3 = 1
x = 1 + 3
x = 4
x = 4
y = 1
z = - 5
Maka x + y - z = 4 + 1 - (- 5)
= 5 + 5
= 10
Jawabannya yang E. 10