Tolong kerjakan sekarang!! butuh sekarang!! ini tentang bangun sebangun dengan kongruen! please
alpharajassa
3) PR² = RQ x RS (6√3)²= 12 x RS (6√3)(6√3) = 12 x RS (6x6)(√3x√3)= 12 x RS (36)(√9)= 12 x RS (36)(3) = 12 x RS 108= 12 x RS RS= 108/12 RS= 9 cm
(6√3)²= 12 x RS
(6√3)(6√3) = 12 x RS
(6x6)(√3x√3)= 12 x RS
(36)(√9)= 12 x RS
(36)(3) = 12 x RS
108= 12 x RS
RS= 108/12
RS= 9 cm
maaf..cman bsa jawab 1
thanks smoga bermanfaat..;)