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= (3^x) x 3^1 - (3^x) x (3^ -1) ---> substitusi y = 3^x
= y x 3 - (y x (1/3)
= 3y - ( y/3)
= 9y/3 - y/3
= 8y /3
c. 2 ( 3^(1- x))
= 2 ( 3^1 . 3^ -x)
= 2 ( 3 x 1/y)
= 2 ( 3/y)
= 6/y