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det A = det B
(x+2)(x) - 3(x-3) = 2(x-1) 2(x+1) - {2(3x+2) -2}
x² + 2x - 3x+ 9 = 4 (x² -1) - (6x + 4 - 2)
x² - x + 9 = 4x² - 4 - 6x- 2
x² - x + 9 = 4x² -6x - 6
x² - 4 x² - x + 6x + 9+6 = 0
-x² + 2x + 15=0
x² - 2x - 15 =0
(x - 5)(x + 3) = 0
x- 5 = 0
x = 5
x+3 = 0
x = - 3
x =( -3, 5)