1. (1 + √2)(3 + √2) = 5 + 4√2
2. (2√3 + √2)(2√3 - √2) = 10
–› No. 1
(1 + √2)(3 + √2)
= (3 + √2) + √2(3 + √2)
= (3 + √2) + (3√2 + 2)
= (3 + 2) + (√2 + 3√2)
= (3 + 2) + (1 + 3)√2
= 5 + 4√2
–› No. 2
(2√3 + √2)(2√3 - √2)
= (2√3)² - (√2)²
= (4√3√3) - 2
= (4 × 3) - 2
= 12 - 2
= 10
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
1. (1 + √2)(3 + √2) = 5 + 4√2
2. (2√3 + √2)(2√3 - √2) = 10
Pembahasan
–› No. 1
(1 + √2)(3 + √2)
= (3 + √2) + √2(3 + √2)
= (3 + √2) + (3√2 + 2)
= (3 + 2) + (√2 + 3√2)
= (3 + 2) + (1 + 3)√2
= 5 + 4√2
–› No. 2
(2√3 + √2)(2√3 - √2)
= (2√3)² - (√2)²
= (4√3√3) - 2
= (4 × 3) - 2
= 12 - 2
= 10