1)M = y2-y1/x2-x1
= 8-(-7)/(-6)-4
= 15/(-6)+(-4)
= 15/(-10)
krna tegak lurus dengan titik P maka gradien menjadi
10/15
= 2/3
2)3x - y + 12 = 0
-y = -3x-12
yg diatas x -1(dikali)
y = 3x + 12
m = 3
krna sejajar, maka m1=m2
y-y1 = m(x-x1)
y-(-1) = 3(x-4)
y+1 + 3x-12
y = 3x-13
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1)M = y2-y1/x2-x1
= 8-(-7)/(-6)-4
= 15/(-6)+(-4)
= 15/(-10)
krna tegak lurus dengan titik P maka gradien menjadi
10/15
= 2/3
2)3x - y + 12 = 0
-y = -3x-12
yg diatas x -1(dikali)
y = 3x + 12
m = 3
krna sejajar, maka m1=m2
y-y1 = m(x-x1)
y-(-1) = 3(x-4)
y+1 + 3x-12
y = 3x-13