Jawab:
Penjelasan dengan langkah-langkah:
Vektor segaris
AC = k (AB)
c - a = k( b - a)
c = k( b- a ) + a
(13, 5, p ) = k( 4, 1, 2) + (1 , 2 , 4)
13 = 4k + 1 ---> k= 3
p = 2k + 4
p = 2(3) + 4
p = 10
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Jawab:
Penjelasan dengan langkah-langkah:
Vektor segaris
AC = k (AB)
c - a = k( b - a)
c = k( b- a ) + a
(13, 5, p ) = k( 4, 1, 2) + (1 , 2 , 4)
13 = 4k + 1 ---> k= 3
p = 2k + 4
p = 2(3) + 4
p = 10