tolong kak di bantu nomor 10!!!.... Question from @fikripriansyah39

fikripriansyah39 @fikripriansyah39

May 2022 2 11 Report

tolong kak di bantu nomor 10!!!

CeliaClaire

$\tt = \frac{2}{a - b} + \frac{3}{ {a}^{2} - {b}^{2} }$

$\tt = \frac{2(a + b)}{(a - b)(a + b)} + \frac{3}{ {a}^{2} - {b}^{2} }$

$\tt = \frac{2a + 2b}{ {a}^{2} - {b}^{2} } + \frac{3}{ {a}^{2} - {b}^{2} }$

$\tt = \frac{2a + 2b + 3}{ {a}^{2} - {b}^{2} }$

Opsi B.

$\pink{\boxed{\red{\boxed{\purple{\mathfrak{\ast ~ \blue{Celia ~ Claire} ~ \ast}}}}}}$

1 votes Thanks 0

xcvi

Jawaban:
$\displaystyle\bf 10.\:B.=\frac{2a+2b+3}{a^2-b^2}$
Penjelasan dgn langkah²
10. Berapa hasil dari
$\displaystyle\rm\frac{2}{a-b}+\frac{3}{a^2-b^2}=\\\\\frac{2}{a-b}+\frac{3}{(a+b)(a-b)}=\\\\\frac{2(a+b)}{(a+b)(a-b)}+\frac{3}{(a+b)(a-b)}=\\\\\frac{2(a+b)+3}{(a+b)(a-b)}=\frac{2(a+b)+3}{a^2-b^2}\\\\\bf B.=\frac{2a+2b+3}{a^2-b^2}$
XCVI

3 votes Thanks 1

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