f(x) = x²- 5 x + 4
sumbu x
x² 5x + 4 = 0
(x - 1) (x - 4)
x = 1 x = 4
titik potong (1,0) (4 0)
sumbu y
y = x²- 5x + 4
x = 0 - y = 0²- 5x 0 + 4
y = 4
titik potong (0,4)
SEMOGA MEMBANTU !
Penjelasan dengan langkah-langkah:
Semoga bermanfaat
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f(x) = x²- 5 x + 4
sumbu x
x² 5x + 4 = 0
(x - 1) (x - 4)
x = 1 x = 4
titik potong (1,0) (4 0)
sumbu y
y = x²- 5x + 4
x = 0 - y = 0²- 5x 0 + 4
y = 4
titik potong (0,4)
SEMOGA MEMBANTU !
Penjelasan dengan langkah-langkah:
x² 5x + 4 = 0
(x - 1) (x - 4)
x = 1 x = 4
titik potong (1,0) (4 0)
sumbu y
y = x²- 5x + 4
x = 0 - y = 0²- 5x 0 + 4
y = 4
titik potong (0,4)
Semoga bermanfaat