Question

Tolong jawabkan soal matik no 21,dengan caranyaa

Answer 1

G(x) = y = (x - 1)/(2x + 1)

maka invers dari g(x)

x = (y - 1)/(2y + 1)

x•(2y + 1) = y - 1

2xy + x = y - 1

2xy - y = -1 - x

y(2x - 1) = (-1 - x)

y = (-1 - x)/(2x - 1)

y = (x + 1)/(1 - 2x)

g⁻¹(x) = (x + 1)/(1 - 2x) ; x ≠ 1/2 ✔

Answer 2

Y = (x - 1 )/(2x + 1)

y(2x + 1) = x - 1

2xy + y = x - 1

2xy - x = - y - 1

x(2y - 1) = -y - 1

x = ( - y - 1)/(2y - 1)

g-¹(x) = (-x - 1)/(2x - 1)

g-¹(x) = ( x + 1) / ( 1 - 2x)

→ x ≠ ½

jawaban : b