SOAL NO.2
DITANYA
nilai x°+y°+z°?( z° tdk ada di soal)
PEMBAHASAN
-12x°+108°=180°(sudut berpelurus)
12x°=72°. x=6
-5x°+2y°+56°=180°(sudut berpelurus)
masukkan(subtitusi) x=6
5(6)°+2y°=124°
30°+2y°=124°. 2y°=94°. y=94/2=47
MAKA x°+y°=6°+47°=53°
semoga membantu :-)
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SOAL NO.2
DITANYA
nilai x°+y°+z°?( z° tdk ada di soal)
PEMBAHASAN
-12x°+108°=180°(sudut berpelurus)
12x°=72°. x=6
-5x°+2y°+56°=180°(sudut berpelurus)
masukkan(subtitusi) x=6
5(6)°+2y°=124°
30°+2y°=124°. 2y°=94°. y=94/2=47
MAKA x°+y°=6°+47°=53°
semoga membantu :-)