Jawab:
f(x) = 2x, g(x) = 2+x
maka (fOg)^-1(x)=
=> (f(g(x))^-1(x)=0
=> (f(2+x))^-1(x)=0
=> f(2+x) =2(2+x)
=> f(x) =4+2x
=> maka f(x)^-1= (x-4)÷2
Penjelasan dengan langkah-langkah:
f(x) = 2x
f^-1(x) = x/2
g(x) = 2+x
g^-1(x) = x-2
(fog)^-1(x) = g^-1(x) o f^-1(x) = g^-1(x/2) = (x/2) -2 = (x-4)/2
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Jawab:
f(x) = 2x, g(x) = 2+x
maka (fOg)^-1(x)=
=> (f(g(x))^-1(x)=0
=> (f(2+x))^-1(x)=0
=> f(2+x) =2(2+x)
=> f(x) =4+2x
=> maka f(x)^-1= (x-4)÷2
Penjelasan dengan langkah-langkah:
f(x) = 2x
f^-1(x) = x/2
g(x) = 2+x
g^-1(x) = x-2
(fog)^-1(x) = g^-1(x) o f^-1(x) = g^-1(x/2) = (x/2) -2 = (x-4)/2