Question

Tolong jawab ya! nomer 29

Answer 1

• Luas permukaan tabung:

2 × π × r × (r + t) = 2 × 22/7 × 7 × (7 + 10) = 748 cm²

• Luas permukaan balok:

2 × (pl + pt + lt) = 2 × (196+140+140) = 2 × 476 = 952 cm²

Luas permukaan bangun tersebut = 748 + 952 = 1.700 cm²

JAWABAN: D. 1.700 CM²

Answer 2

2×22/7×7×(7+10)=748cm²

2×(14×14)+(14×10)+(14+10)

2×(196+140+140)

2×476=962 cm²

748+962=d 1.700cm

maaf kalau salah dan semoga membantu