Question

tolong jawab soal pada gambar!​

Answer 1

[tex] \frac{1}{2} V = 1.540 \: {cm}^{3} \\ V = 1.540 \: {cm}^{3} \times \frac{2}{1} \\ V = 3.080 \: {cm}^{3} \\ \\ tinggi \: kaleng \: tabung \\ V \div (\pi \times r \times r) \\ 3.080 \: {cm}^{3} \div ( \frac{22}{7} \times 10 \: cm \times 10 \: cm) \\ 3.080 \: {cm}^{3} \div \frac{2.200}{7} \: {cm}^{2} \\ 3.080 \: {cm}^{3} \times \frac{7}{2.200 \: {cm}^{2} } \\ 9,8 \: cm[/tex]

Answer 2

Verified answer

Bangun Ruang Sisi Lengkung

[Tabung]

..

[tex]\boxed{V~Tabung = \pi \times r {}^{2} \times t }[/tex]

..

Diberikan

• Kaleng Tabung
• Volume Setengah Bagian 1540 cm³
• Jari-jari 10 cm

Tentukan

• tinggi

Hasil dan Perhitungan

[tex]tinggi = \frac{volume \: total}{\pi \times r \times r} [/tex]

[tex]~~~~~~~~~~~~= \frac{1540 \times 2}{( \frac{22}{7}) \times 10 \times 10 } [/tex]

[tex]~~~~~~~~~~~~= \frac{3080}{100} \times \frac{7}{22} [/tex]

[tex]~~~~~~~~~~~~= \frac{\cancel{3080} \: {}^{140} }{100} \times \frac{7}{\cancel{22} }[/tex]

[tex]~~~~~~~~~~~~= \frac{140}{100} \times 7[/tex]

[tex]~~~~~~~~~~~~=1.4 \times 7[/tex]

[tex]~~~~~~~~~~~~=9.8 \: cm[/tex]

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[tex]\begin{array}{lr}\texttt{Rate 1.0 Jika Kalian Iri dengan}\\\\ \texttt{Yang Mulia Maharaja Danial Alf'at}\end{array}[/tex] ☝️

[tex]\boxed{\colorbox{ccddff}{Answered by Danial Alf'at}}\boxed{\colorbox{ccddff}{15/03/23}}[/tex]