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P = 30 W
V = 120 V
Rk = 0,2
P = V . I
Kuat arus yang mengalir:
I = P / V
I = 30 / 120
I = 0,25 A
V = I . R
Hambatan lampu :
R = V / I
R = 120 / 0,25
R = 480 Ω
Jika terjadi hubung singkat:
Ι = V / Rk
I = 120 / 0,2
I = 600 A