Tolong jawab soal diatas soalnya buat besok, karena ini penting ya plis aku mohon banget jawabya soal diata pr itu plistapi disuruhnya pake cara aku mohon ya pake cara ya
ghuroba
1.) luas trapesium = ½ × jumlah sisi sejajar × tinggi 360 = ½ × (25 + 15) × tinggi tinggi = 360 : (½ × 40) = 360/20 = 18cm 2.) luas segitiga = ½ × alas × tinggi 480 = ½ × 40 × tinggi tinggi = 480 : (½ × 40) = 480/20 = 24cm 3.) luas lingkaran = π × r × r r = ½ × diameter = ½ × 50 = 25cm luas lingkaran = 3,14 × 25 × 25 = 1.962,5cm² 4.) luas lingkaran = π × r × r 616 = 22/7 x r² r = √616 : 22/7 = √196 = 14cm diameter = 2 × jari jari = 2 × 14 = 28cm 5a.) luas permukaan = 3 × luas persegi = 3 × 12 × 12 = 432cm² 5b.) luas arsiran = ½ × luas permukaan = ½ × 16 × 38 = 304cm²
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Gishella2
1. t = (a+b) / L:2 = ( 25 cm + 15 cm ) / 360 cm^2 : 2 = 40 cm / 180 cm = 4,5 cm 2. t = a / L : 2 = 40 cm / 480 cm^2 : 2 = 40 cm / 240 cm = 6 cm 3. r = d : 2 = 50 cm : 2 = 25 cm L = phi x r^2 = 3,14 x 25 cm x 25 cm = 78,5 cm x 25 cm = 1962,5 cm^2
360 = ½ × (25 + 15) × tinggi
tinggi = 360 : (½ × 40) = 360/20 = 18cm
2.) luas segitiga = ½ × alas × tinggi
480 = ½ × 40 × tinggi
tinggi = 480 : (½ × 40) = 480/20 = 24cm
3.) luas lingkaran = π × r × r
r = ½ × diameter = ½ × 50 = 25cm
luas lingkaran = 3,14 × 25 × 25 = 1.962,5cm²
4.) luas lingkaran = π × r × r
616 = 22/7 x r²
r = √616 : 22/7 = √196 = 14cm
diameter = 2 × jari jari = 2 × 14 = 28cm
5a.) luas permukaan = 3 × luas persegi = 3 × 12 × 12 = 432cm²
5b.) luas arsiran = ½ × luas permukaan = ½ × 16 × 38 = 304cm²
= ( 25 cm + 15 cm ) / 360 cm^2 : 2
= 40 cm / 180 cm
= 4,5 cm
2. t = a / L : 2
= 40 cm / 480 cm^2 : 2
= 40 cm / 240 cm
= 6 cm
3. r = d : 2
= 50 cm : 2
= 25 cm
L = phi x r^2
= 3,14 x 25 cm x 25 cm
= 78,5 cm x 25 cm
= 1962,5 cm^2