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2][((x+6)'log x)^-1 + x'log (x - 1) = 2 + (x'log x)^-1
x'log ((x + 6)(x - 1)) = 2 + 1
(x + 6)(x - 1) = x³
x² + 5x - 6 = x³
x³ - x² - 5x + 6 = 0
(x - 2)(x² + x - 3) = 0
Pembuat nol :
x - 2 = 0
x = 2
x² + x - 3 = 0
Rumus abc
x1.2 = (-1 ± √13)/2
x = (-1 + √13)/2 memenuhi
Nilai x yg memenuhi :
2 dan (-1 + √13)/2
4][
²log (10 - x) < 1
10 - x < 2^1
-x < 2 - 10
x > -8/-1
x > 8 ... (1)
syarat numerus :
10 - x > 0
-x > -10
x < 10 ... (2)
NiLai x yg memenuhi :
Irisan (1) dan (2)
8 < x < 10