Question

Tolong jawab, saya doain dapat balasannya Aminn​

Answer 1

19)

<KLM = 30

<MKL = 90

maka <KML = 180 - (30+90) = 180 - 120 = 60 (C)

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20)

<ACB = 40

<CAB = <CBA

maka = (180 - 40) : 2 = 140 : 2 = 70 (B)

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21) D. lingkaran

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22) A. bentuk Z

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semoga membantu

maaf jika kalau ada yang salah

Answer 2

19)
<MKL = 90°
<KLM = 30°
<KML = 180° - (90° + 30°)
= 180° - 120°
= 60° (C)

20)
<ACB = 40°
<CDB = 90°
<DCB = 40÷2 = 20°
<CBA = 180° - (90° + 20°)
= 180° - 110°
= 70° (B)

21) D. Lingkaran

22) A. Z

23)
<GDE = <EFG
<EFG = 180° - (20° + 40°)
= 180° - 60°
= 120° (A)