Tolong Jawab pertanyaan ini dong.. Aku nggak ngerti cara kerjanya :).... Question from @yosuadhch

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October 2018 2 8 Report

Tolong Jawab pertanyaan ini dong.. Aku nggak ngerti cara kerjanya
:)

cahyatirizka M = 100 g = 0,1 kg
deltaT p-q = 5

Q(p-q) = 0,1 x 2100 x 5
=1050 J

Q(q-r) = 0,1 x 340.000
= 34.000 J

Q(p-r) = 1.050 + 34.000
=35.050 J (C)

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izharulhaq78 $m=100g=0,1kg \\ c_{es}=2100J/kg^oC \\ L=340.000J/kg \\ T_1=-5^oC \\ T_2=0^oC \\ \\ \Sigma Q_{P-R} = ? \\ \\ Q_{P-Q}=mc_{es}\Delta T \\ Q_{P-Q}=mc_{es}(T_2-T_1) \\ Q_{P-Q}=0,1\times2100(0-(-5)) \\ Q_{P-Q}=1\times210(5) \\ Q_{P-Q}=1050J \\ \\ Q_{Q-R}=mL \\ Q_{Q-R}=0,1\times340.000 \\ Q_{Q-R}=1\times34000 \\ Q_{Q-R}=34.000J \\ \\ \Sigma Q_{P-R}=Q_{P-Q}+Q_{Q-R} \\ \Sigma Q_{P-R}=1050+34.000 \\ \Sigma Q_{P-R}=35.050J$

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