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a = 3; b = - 3 dan c = -12
D = b² - 4ac
D = (-3)² - 4(3)(-12)
= 9 + 144
= 153
Rumus ABC
x1 = (-b + √D)/2a x2 = (-b - √D )/2a
x1 = ( 3 + √153)/6 x2 = (3 - √153)6
Jadi faktor-faktor dair 3x² - 3x - 12 adalah (x - ( 3 - √153)/6) dan
(x -( 3 + √153)/6)