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f = S.S₁/ S+S₁
6.12/ 6+12
= 72/18
=4
jarak bayangan kedua s= 6+1 = 7
S₂= s. f/ s-F
7.4/ 7-4
=28/ 3
=9,3
No.3
S= 12
f= 4
S₁= 1/f- 1/S
=1/4- 1/12
=3/12-1/12
=2/12
=12/2
=6
perbesarannya
S₁/S : 6/12
: 1/2 kali