Question

tolong jawab nomor 4 dan 5 plissssssssssss

Answer 1

Limit

Nomor 4

[tex]\displaystyle\lim_{x \to 4} \: \frac{12 + x - x {}^{2} }{ \sqrt{x} - 2 }[/tex]

[tex]\displaystyle\lim_{x \to 4} \: \frac{ - {x}^{2} + 4x - 3x + 12 }{ \sqrt{x} - 2 }[/tex]

[tex]\displaystyle\lim_{x \to 4} \: \frac{ - {x}(x - 4) - 3(x - 4) }{ \sqrt{x} - 2 }[/tex]

[tex]\displaystyle\lim_{x \to 4} \: \frac{ - (x - 4) \times (x + 3) }{ \sqrt{x} - 2 }[/tex]

[tex]\displaystyle\lim_{x \to 4} \: \frac{ - ( \sqrt{x} - 2)( \sqrt{x} + 2) \times (x - 3) }{ \sqrt{x} - 2 }[/tex]

[tex]\displaystyle\lim_{x \to 4} \: - \sqrt{x} x - 3 \sqrt{x} - 2x + 6[/tex]

[tex] = - \sqrt{4} \times 4 - 3 \sqrt{4} - 2 \times 4 - 6[/tex]

[tex] = - 28[/tex]

..

Nomor 5

lim x → 5

(d/dx(2x - 10))/(d/dx(√[x+4] - 3)

(2 - 0)/(d/dx(√[x+4]) - d/dx(3))

(2)/(1/(2√[x+4] - 0)

(2)/(1/2√[x+4]

(2 × 2√[x+4]/1)

(4√[x+4])

= 4√(5 + 4)

= 4√9

= 4.3

= 12

..

[tex]\begin{array}{lr}\texttt{Rate 1.0 Jika Kalian Iri dengan}\\\\ \texttt{Yang Mulia Maharaja Danial Alf'at}\end{array}[/tex] ☝️

[tex]\boxed{\colorbox{ccddff}{Answered by Danial Alf'at | 20 - 03 - 2023}}[/tex]