Question

Tolong jawab no 17 dongg.

Answer 1

PH = 5 - log 2
[H+] = 2. 10^-5

[H+] = ka Ma.Va.Na / Mb. Vb. Nb
2.10^-5 = 10^-5 . 0.1 x Va x 1 / 0,1 x 1 x Vb
2 = 0,1Va/0,1Vb
0,2Vb = 0,1Va

Mungkin Perbandingannya

CH3COOH  = NaOH
60 = 90

yang D mungkin xD