Penjelasan dengan langkah-langkah:
Mohon koreksinya
Semoga membantu :)
Jawab:
trigonometri
soal
tan θ =- 8/15 = y/x
x= 15, y = 8 , r = √x²+y²
r = √15²+8² = √289
r =17
tan θ< 0 dan sin θ > 0 , maka θ di kuadran II
maka sin θ = y/r = 8/17
a. cos θ = - x/r = - 15/17
b. csc θ= r/y = 17/8
c. sin θ. cos θ+ cos θ sin θ= 2 sin θ cos θ
= 2 (8/17)(- 15/17)
= - 240/289
d. csc θ/cot θ =
= r/y : - x/y
= -r/x
= - 17/15
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Penjelasan dengan langkah-langkah:
Mohon koreksinya
Semoga membantu :)
Jawab:
Penjelasan dengan langkah-langkah:
trigonometri
soal
tan θ =- 8/15 = y/x
x= 15, y = 8 , r = √x²+y²
r = √15²+8² = √289
r =17
tan θ< 0 dan sin θ > 0 , maka θ di kuadran II
maka sin θ = y/r = 8/17
a. cos θ = - x/r = - 15/17
b. csc θ= r/y = 17/8
c. sin θ. cos θ+ cos θ sin θ= 2 sin θ cos θ
= 2 (8/17)(- 15/17)
= - 240/289
d. csc θ/cot θ =
= r/y : - x/y
= -r/x
= - 17/15