Jawaban:
1. luas permukaan balok (1)
=2(pl+pt+lt)
=2x((36×12)+(36×12)+(12×12))
=2x(432+432+144)
=2×1008
=2016 cm
luas permukaan kubus (2)
=6xsxs
=6×12×12
=864 cm
digabungkan:luas permukaan balok + luas permukaan kubus
=2016+864
=2880 cm
2. luas lingkaran + luas selimut tabung + luas selimut kerucut
22/7 x 7 x 7 + 22/7 x 14 x 32 + 22/7 x 7 x 10
154 +1408 + 220 = 1782 cm2
3. luas permukaan= (20x12x3) + (12x12×7) + (8x12) = 720 + 1.008 +96 = 1.824 Cm²
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Jawaban:
1. luas permukaan balok (1)
=2(pl+pt+lt)
=2x((36×12)+(36×12)+(12×12))
=2x(432+432+144)
=2×1008
=2016 cm
luas permukaan kubus (2)
=6xsxs
=6×12×12
=864 cm
digabungkan:luas permukaan balok + luas permukaan kubus
=2016+864
=2880 cm
2. luas lingkaran + luas selimut tabung + luas selimut kerucut
22/7 x 7 x 7 + 22/7 x 14 x 32 + 22/7 x 7 x 10
154 +1408 + 220 = 1782 cm2
3. luas permukaan= (20x12x3) + (12x12×7) + (8x12) = 720 + 1.008 +96 = 1.824 Cm²