No. 2
Diket =
Dit =
Jawab
[tex]2 \frac{1}{4} - \frac{1}{6} = \frac{9}{4} - \frac{1}{6} \\ \\ = \frac{27 - 2}{12} = \frac{25}{12} = 2 \frac{1}{12} kg \\ [/tex]
Jadi gulanya skrg ada 2 1/12 kg
No. 3
[tex]6 - \frac{2}{3} - \frac{3}{5} = \frac{6}{1} - \frac{2}{3} - \frac{3}{5} \\ \\ = \frac{90 - 10 - 9}{15} = \frac{71}{15} = 4 \frac{11}{15} kg[/tex]
jdi yg msh tersisa ad 4 11/15 kg
No. 4
[tex]12 \frac{1}{4} - 5 \frac{2}{5} = \frac{49}{4} - \frac{27}{5} \\ \\ = \frac{245 - 108}{20} = \frac{137}{20} = 6 \frac{17}{20} m[/tex]
jdi sisa kawat masih ada 6 17/20 m
smg mmbntu
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
No. 2
Diket =
Dit =
Jawab
[tex]2 \frac{1}{4} - \frac{1}{6} = \frac{9}{4} - \frac{1}{6} \\ \\ = \frac{27 - 2}{12} = \frac{25}{12} = 2 \frac{1}{12} kg \\ [/tex]
Jadi gulanya skrg ada 2 1/12 kg
No. 3
Diket =
Dit =
Jawab
[tex]6 - \frac{2}{3} - \frac{3}{5} = \frac{6}{1} - \frac{2}{3} - \frac{3}{5} \\ \\ = \frac{90 - 10 - 9}{15} = \frac{71}{15} = 4 \frac{11}{15} kg[/tex]
jdi yg msh tersisa ad 4 11/15 kg
No. 4
Diket =
Dit =
Jawab
[tex]12 \frac{1}{4} - 5 \frac{2}{5} = \frac{49}{4} - \frac{27}{5} \\ \\ = \frac{245 - 108}{20} = \frac{137}{20} = 6 \frac{17}{20} m[/tex]
jdi sisa kawat masih ada 6 17/20 m
smg mmbntu