Question

Tolong jawab in cuma nmr 3
pakek cara

Answer 1

A.) keliling ⊙ = panjang busur AB x 6 = 22 x 6 = 132

b.) jari2 lingkaran = keliling / 2π = 132 / 2 * 22/7 = 1452/7 =207/3/7

c.) luas ⊙ = π r ² = 22/7 * (1452/7)² = 135226

d.) panjang busur cod (30°) = 1/2 dari busur aob (60°) = 1/2 * 22 = 11 cm

e.) luas juring boc (90°) = (luas ⊙ : 4) - luas Δ boc = (135226 / 4) - (1452/7*1452/7*1/2) = 135226/4 - 1054152/49 = 3313037/98 - 2108304/98 = 1204733/98 = 12293/19/98

maaf ya kalo salah