Question

Tolong jawab gambar soal matematika ini ya teman

Answer 1

Ax² + (x + b)(2x - 1)  ≡ (bx - 2)(x + 3) + c
ax² + 2x² - x + 2bx - b ≡ bx² + 3bx - 2x - 6 + c
(a + 2)x²  + (-1 + 2b)x - b ≡ bx² + (3b - 2)x - (6 - c)

didapat persamaan
a + 2 = b........1
-1 + 2b = 3b - 2..........2
b = 6 - c..........3


-1 + 2b = 3b - 2
-1 + 2 = 3b - 2b
1 = b
substitusikan b = 1 ke persamaan 1 dan 2
a + 2 = b
a + 2 = 1
a = 1 - 2 = - 1

b = 6 - 5
1 = 6 - c
c = 6 - 1 = 5