Question

Tolong jawab dengan caranya

Answer 1

Persamaan garis singgung lingkaran x²+y²-6x+4y-12=0 dititik (7,1)
=> y1.y+x1.x+A/2.(x+x1)+B/2.(y+y1)+c=0
=> 1y+7x-3(x+7)+2(y+1)-12 = 0
=> y+7x-3x-21+2y+2-12 = 0
=> 4x+3y-31 = 0