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(i) perpotongan sumbu X maka y=0
x² + x + 3 = 0
D=b²-4ac = 1² -4.1.3 = -11
D<0 maka akarnya maya.
(ii) perpotongan sumbu Y maka x=0
x²+x+3=(0)²+(0)+3=3
maka titiknya (0,3)
(iii) sumbu simetri x=-b/2a
x = -b/2a = -1/2
(iv) nilai minimum y=-D/4a
y = -(-11)/4(1) = 11/4
(v) titik puncaknya = (-1/2 ; 11/4)
grafik nya di lampiran yah..
titik B itu titik puncak
titik C itu perpotongan sumbu Y
have a nice day... ;-)