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(2k+ 16) - (3k+12) = (44-k) - ( 2k+16)
- k - 4 = -3k + 28
2k = 32
k = 12
urutan aritmatikanya :
3k + 12 , 2k+16, 44- k
3(12)+12, 2(12)+16 , 44- 12
36 +12 , 24 + 16 , 32
48, 40 , 32
b = 48-40 = -8
un= a + (n-1)b = 48+ (n-1)-8
= 48 - 8n +8
=56- 8n
= 8 ( 7 - n) ... c
U2-U1 = U3- U2
(2k+ 16) - (3k+12) = (44-k) - ( 2k+16)
2k - 3k + 16 - 12 = -k -2k + 44 - 16
- k + 4 = -3k + 28
-k + 3k = 28 - 4
2k = 24
k = 12
jadi U1 = 3k + 12
= 3(12) + 12
= 36 + 12
= 48
U2 = 2k + 16
= 2(12) +16
= 24 + 16
= 40
U3 = 44- k
= 44- 12
= 32
b = 48-40 = -8
un = a + (n-1)b
= 48+ (n-1)(-8)
= 48 - 8n +8
= 56- 8n
= 8 ( 7 - n)
jawaban C