wt = 3 gram
wp = 100 gram
ΔTb = 0,54°C
Kb = 2,52°C/m
Mr = ………………….?
ΔTb = wt/Mr x 1000/Wp x Kb
0,54 = 3/Mr x 1000/100 x 2,52
0,54 = 75,6/Mr
Mr = 75,6/0,54
Mr = 140
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Verified answer
wt = 3 gram
wp = 100 gram
ΔTb = 0,54°C
Kb = 2,52°C/m
Mr = ………………….?
ΔTb = wt/Mr x 1000/Wp x Kb
0,54 = 3/Mr x 1000/100 x 2,52
0,54 = 75,6/Mr
Mr = 75,6/0,54
Mr = 140