diketahui:
F = 200 N
m = 40 kg
a = 3 m/s^2
penyelesaian:
ΣF = m.a
Ftarik - Fgesek = m.a
200 N - Fgesek = 40 kg . 3 m/s^2
(-Fgesek) = 120 N - 200 N
(-Fgesek) = (-80) N
Fgesek = ((-80)/(-1)) N
Fgesek = 80 N
Penjelasan:
Dilampirkan
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diketahui:
F = 200 N
m = 40 kg
a = 3 m/s^2
penyelesaian:
ΣF = m.a
Ftarik - Fgesek = m.a
200 N - Fgesek = 40 kg . 3 m/s^2
(-Fgesek) = 120 N - 200 N
(-Fgesek) = (-80) N
Fgesek = ((-80)/(-1)) N
Fgesek = 80 N
Penjelasan:
Dilampirkan