Jawab:
27. jarak kedua pusat (p)
d² = p² - (r1 + r2)²
16² = p² - (8+4)²
256 = p² - (12)²
p² = 256 + 144
p² = 400
p = √400
p = 20
jawban A
28. d = √p² - (r1-r2)²
d = √20² - (14-2)²
d = √400 - 144
d = √256
d = 16
jawaban A
Penjelasan dengan langkah-langkah:
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Jawab:
27. jarak kedua pusat (p)
d² = p² - (r1 + r2)²
16² = p² - (8+4)²
256 = p² - (12)²
p² = 256 + 144
p² = 400
p = √400
p = 20
jawban A
28. d = √p² - (r1-r2)²
d = √20² - (14-2)²
d = √400 - 144
d = √256
d = 16
jawaban A
Penjelasan dengan langkah-langkah: