6. K = π x D = 3,14 x 10cm
= 31,4 cm
7. pertanyaannya apa?
jika pertanyaannya panjang grs singgung persekutuan luar maka:
pjg grs singgung = P
jarak titik pusat = J
jari² lingkaran 1 = 10 cm
jari² lingkaran 2 = 6 cm
P² = J² - (10-6)² = 10² - 4²
= 100 - 16 = 84
P =√84 = √4 x √21 = 2√21 cm
8. misal, pjg grs singgung = P
P² = 10² - ( 5+3)² = 10² - 8²
= 100 - 64 = 36
P = √36 = 6 cm
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6. K = π x D = 3,14 x 10cm
= 31,4 cm
7. pertanyaannya apa?
jika pertanyaannya panjang grs singgung persekutuan luar maka:
pjg grs singgung = P
jarak titik pusat = J
jari² lingkaran 1 = 10 cm
jari² lingkaran 2 = 6 cm
P² = J² - (10-6)² = 10² - 4²
= 100 - 16 = 84
P =√84 = √4 x √21 = 2√21 cm
8. misal, pjg grs singgung = P
P² = 10² - ( 5+3)² = 10² - 8²
= 100 - 64 = 36
P = √36 = 6 cm