Materi : Kesebangunan dan Kekonggruenan
HF/HI = GF/GE
HF/6 = 10/24
HF = 6 × 10/24
HF = 10/4
{ HF = 2,5 } { d. }
Materi : Garis dan Sudut
∠P + ∠Q = 180°
( 3x ) + ( 4x + 26° ) = 180°
7x = 180° - 26°
7x = 154°
x = 154°/7
{ x = 22° }
Maka { ∠Q = ( 4x + 26° ) = 88° + 26° = 114° } { c. }
∠A3 = ∠B3
∠A3 + ∠A2 = 180°
5x + 4x = 180°
9x = 180°
x = 180°/9
x = 20°
Maka { ∠A3 = 5x = 100° }
∠B3 = ∠A3
8p = 100°
p = 100°/8
{ p = 12,5° } { a. }
Semoga bisa membantu
HI = 6cm
GE = 24cm
GF = 10cm
HF...?
24 HF = 6 × 10
24 HF = 60
HF = 2,5cm(D.)
P+q=180°
3x+4x+26=180
7x+26=180
7x=180-26
7x=154
x=22°
p=3x
p= 3 x 22
p=66°
q=4x+26
q=4(22)+26
q= 114°(C.)
∠A₂ + ∠A₃ = 180°
4x + 5x = 180°
Karena ∠A₃ dan ∠B₃ sehadap, maka
∠B₃ = ∠A₃
8p° = 5x
8p° = 5 × 20
p = 12,5°(A.)
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
Soal Nomor 3
Materi : Kesebangunan dan Kekonggruenan
HF/HI = GF/GE
HF/6 = 10/24
HF = 6 × 10/24
HF = 10/4
{ HF = 2,5 } { d. }
Soal Nomor 4
Materi : Garis dan Sudut
∠P + ∠Q = 180°
( 3x ) + ( 4x + 26° ) = 180°
7x = 180° - 26°
7x = 154°
x = 154°/7
{ x = 22° }
Maka { ∠Q = ( 4x + 26° ) = 88° + 26° = 114° } { c. }
Soal Nomor 5
Materi : Garis dan Sudut
∠A3 = ∠B3
Cari Besar ∠A3
∠A3 + ∠A2 = 180°
5x + 4x = 180°
9x = 180°
x = 180°/9
x = 20°
Maka { ∠A3 = 5x = 100° }
Langsung Saja
∠B3 = ∠A3
8p = 100°
p = 100°/8
{ p = 12,5° } { a. }
Semoga bisa membantu
No. 3.
HI = 6cm
GE = 24cm
GF = 10cm
HF...?
24 HF = 6 × 10
24 HF = 60
HF = 2,5cm(D.)
No. 4.
P+q=180°
3x+4x+26=180
7x+26=180
7x=180-26
7x=154
x=22°
p=3x
p= 3 x 22
p=66°
q=4x+26
q=4(22)+26
q= 114°(C.)
No. 5.
∠A₂ + ∠A₃ = 180°
4x + 5x = 180°
x = 20°
Karena ∠A₃ dan ∠B₃ sehadap, maka
∠B₃ = ∠A₃
8p° = 5x
8p° = 5 × 20
p = 12,5°(A.)