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a. x'2 - 1 = 0
x'2 = 1
x = akar 1
x = 1
jd, akar akarnya 1 dan -1
b. 4x'2 + 4x + 1 = 0
(2x+1) (2x+1)=0
2x + 1 = 0 || 2x + 1 = 0
2x = -1 || 2x = 0
x = - 1/2 || x = - 1/2
jd akar akarnya 1/2 ( akar kembar )