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t = 16
luas alas = π x r²
= 3,14 x 4,25²
= 56,71625
luas alas = luas tutup = 56,71625
luas selimut = 2 π r t
= 2 x 3,14 x 4,25 x 16
= 427,04
lluas permukaan = (56,71625 x 2) + 427,04
= 540, 4725
pake rumus
luas permukaan = 2 π r ( r + t)
= 2 x 3,14 x 4,25 x ( 4,25 + 16)
= 2 x 3,14 x 4,25 x 20,25
= 540,4725
kesimpulan :
hasilnya sama....
mungkin karena pembulatan ?