Penjelasan dengan langkah-langkah:
D.
a = 32
b = 243
[tex]2 \sqrt{a} + 3 \sqrt{b} \\ = 2 \sqrt{32} + 3 \sqrt{243} \\ = 2 \sqrt{ {2}^{5} } + 3 \sqrt{ {3}^{5} } \\ = 2 \times {2}^{2} \times {2}^{ \frac{1}{2} } + 3 \times {3}^{2} \times {3}^{ \frac{1}{2} } \\ = {2}^{ \frac{3}{2} } + {3}^{ \frac{3}{2} } [/tex]
E.
[tex] \frac{ \sqrt{2} + 2 \sqrt{3} }{3 \sqrt{5} - 6} \\ = \frac{ \sqrt{2} + 2 \sqrt{3} }{ 3 \sqrt{5} - 6 } \times \frac{ {3 \sqrt{5 } + 6} }{3 \sqrt{5} + 6 } \\ = \frac{3 \sqrt{10} + 6 \sqrt{2} + 6 \sqrt{15} + 12 \sqrt{3} }{9 \times 5 + 18 \sqrt{5} - 18 \sqrt{5} - 36 } \\ = \frac{3 \sqrt{10} + 6 \sqrt{2} + 6 \sqrt{15} + 12 \sqrt{3} }{45 - 36} \\ = \frac{3 \sqrt{10} + 6 \sqrt{2} + 6 \sqrt{15} + 12 \sqrt{3} }{9}[/tex]
[tex]semua \: dibagi \: 3 \\ = \frac{ \sqrt{10} + 2 \sqrt{2} + 2 \sqrt{15} + 4 \sqrt{3} }{3} [/tex]
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Penjelasan dengan langkah-langkah:
D.
a = 32
b = 243
[tex]2 \sqrt{a} + 3 \sqrt{b} \\ = 2 \sqrt{32} + 3 \sqrt{243} \\ = 2 \sqrt{ {2}^{5} } + 3 \sqrt{ {3}^{5} } \\ = 2 \times {2}^{2} \times {2}^{ \frac{1}{2} } + 3 \times {3}^{2} \times {3}^{ \frac{1}{2} } \\ = {2}^{ \frac{3}{2} } + {3}^{ \frac{3}{2} } [/tex]
E.
[tex] \frac{ \sqrt{2} + 2 \sqrt{3} }{3 \sqrt{5} - 6} \\ = \frac{ \sqrt{2} + 2 \sqrt{3} }{ 3 \sqrt{5} - 6 } \times \frac{ {3 \sqrt{5 } + 6} }{3 \sqrt{5} + 6 } \\ = \frac{3 \sqrt{10} + 6 \sqrt{2} + 6 \sqrt{15} + 12 \sqrt{3} }{9 \times 5 + 18 \sqrt{5} - 18 \sqrt{5} - 36 } \\ = \frac{3 \sqrt{10} + 6 \sqrt{2} + 6 \sqrt{15} + 12 \sqrt{3} }{45 - 36} \\ = \frac{3 \sqrt{10} + 6 \sqrt{2} + 6 \sqrt{15} + 12 \sqrt{3} }{9}[/tex]
[tex]semua \: dibagi \: 3 \\ = \frac{ \sqrt{10} + 2 \sqrt{2} + 2 \sqrt{15} + 4 \sqrt{3} }{3} [/tex]