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AB=3/4 gelombang
1 gelombang=4/3×30
=40cm
t=4
λ=s/t
λ=40/4
λ=10cm/s
4.
AB= 1 1/4 gelombang=250cm
1 gelombang = 4/5×250
=200cm
t=2s
λ=s/t
=200/2
=100cm/s
5.
AC=1/2 gelombang
1 gelombang=2/1×0,2
=0,4s
F=n/t
=1/0,4
=1×10/4
=2,5Hz
Amplitudo=simpangan terjauh dari awal getaran=5+5=10cm
Jawaban : 2,5Hz dan 10cm