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Det A = (x+6).x - 1(2x-5)
= x² + 6x - 2x - 5
= x² + 4x - 5
Det A = 0
x² + 4x - 5 = 0
(x-1)(x+5) = 0
Jadi
----> x-1 = 0 maka x = 1
-----> x + 5 = 0 maka x = -5
Jadi agar tidak mempunayai invers nilai x dalam matriks A yaitu nilainya 1 atau -5.
Semoga membantu... ^_^