gradien garis yang melalui titik (-2, 3) dan (4, -1)
m = (y2 - y1) / (x2 - x1)
m = (-1 - 3) / (4 - (-2))
m = (-4)/6
m = -2/3
Karena tegak lurus, maka :
m1 . m2 = -1
-2/3 . m2 = -1
m2 = 3/2
Melalui titik (2, -5)
Persamaan garis
y - y1 = m(x - x1)
y - (-5) = 3/2(x - 2)
2(y + 5) = 3(x - 2)
2y + 10 = 3x - 6
3x - 2y - 6 - 10 = 0
3x - 2y - 16 = 0
Jawaban B
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gradien garis yang melalui titik (-2, 3) dan (4, -1)
m = (y2 - y1) / (x2 - x1)
m = (-1 - 3) / (4 - (-2))
m = (-4)/6
m = -2/3
Karena tegak lurus, maka :
m1 . m2 = -1
-2/3 . m2 = -1
m2 = 3/2
Melalui titik (2, -5)
Persamaan garis
y - y1 = m(x - x1)
y - (-5) = 3/2(x - 2)
2(y + 5) = 3(x - 2)
2y + 10 = 3x - 6
3x - 2y - 6 - 10 = 0
3x - 2y - 16 = 0
Jawaban B