Jawaban:
L1: 6 × s²
= 6 × 5²
= 5² => 25
= 6 × 25 = 150 cm²
L2: ( 2 × p × l ) + ( 2 × p × t ) + (2 × l × t )
= ( 2 × 10 cm × 5 cm ) + ( 2 × 10 cm × 5 cm ) + ( 2 × 5 cm × 5 cm )
= 100 cm + 100 cm + 50 cm => 250 cm²
Jadi, Luas Permukaan bangun di samping adalah L1+L2 = 150 cm² + 250 cm² = 400 cm²
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Jawaban:
L1: 6 × s²
= 6 × 5²
= 5² => 25
= 6 × 25 = 150 cm²
L2: ( 2 × p × l ) + ( 2 × p × t ) + (2 × l × t )
= ( 2 × 10 cm × 5 cm ) + ( 2 × 10 cm × 5 cm ) + ( 2 × 5 cm × 5 cm )
= 100 cm + 100 cm + 50 cm => 250 cm²
Jadi, Luas Permukaan bangun di samping adalah L1+L2 = 150 cm² + 250 cm² = 400 cm²